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1.HCF = 12, LCM = 180, one number = 36. Find the other number.

Answer:60

 For two positive integers:

(number 1)×(number 2)=HCF×LCM

Given,H.C.F = 12, L.C.M= 180, number 1 = 36

So the other number =(12×180)/36=.

Answer: 60

2.HCF = 8, LCM = 160, one number = 4. Find the other number.

Answer:320

 For two positive integers:

(number 1)×(number 2)=HCF×LCM

Given,H.C.F = 8, L.C.M= 160, number 1 = 4

So the other number =(8×160)/4=32.

Answer: 320

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